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In the circuit shown in figure, the curr...

In the circuit shown in figure, the current is to measured. What is the value of the current if the ammeter shown (i) is a galvanometer with a resistance `R_G=60*00Omega`. (ii) is a galvanometer described in (i) but converted to an ammeter by a shunt resistance `r_s=0*02Omega`, (iii) is an ideal ammeter with zero resistance?

Text Solution

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Let G be the resistance of ammeter (i.e. galvanometer). Then current in the circuit,
`I=(epsilon)/(R+G)=(3*00)/(3*00+60*00)=0*048A`.
(ii) When the ammeter (i.e., galvanometer) is shunted with resistance S, its effective resistance,
`R_p=(GS)/(G+S)=(60xx0*02)/(60+0*02)~~0*02Omega`
Current in the circuit,
`I=(epsilon)/(R+R_p)=(3*00)/(3*00+*02)~~0*99A`.
(iii) For the ideal ammeter with zero resistance current, `I=(3*00)/(3*00)=1*00A`.
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