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A bar magnet having a magnetic moment of...

A bar magnet having a magnetic moment of `1.0 xx 10^4 J T^(-1)` is free to rotate in a horizontal plane. A horizontal magnetic field `B = 4 xx 10^(-5) T` exists in the space. Find the work done in rotating the magnet slowly from a direction parallel to the field to a direction `60^@` from the field.

Text Solution

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Here, `M=1*0xx10^4J//T`, `B=4xx10^-5T`, `W=?theta_1=0^@`, `theta_2=60^@`
`W=-MB(costheta_2-costheta_1)=-1*0xx10^4xx4xx10^-5(cos60^@-cos60^@)=-0*4(1/2-1)=0*2J`
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