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At a place, the horizontal component of ...

At a place, the horizontal component of earth's magnetic field is B and angle of dip is `60^@`. What is the value of horizontal component of earth's magnetic field at equator?

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To find the horizontal component of Earth's magnetic field at the equator given the horizontal component \( B \) at a certain place and the angle of dip \( \delta = 60^\circ \), we can follow these steps: ### Step 1: Understand the relationship between the components of the magnetic field The horizontal component \( H \) of the Earth's magnetic field at any location is related to the resultant magnetic field \( R \) and the angle of dip \( \delta \) by the formula: \[ H = R \cos(\delta) \] ...
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Knowledge Check

  • The horizontal component of earth’s magnetic field is zero at:

    A
    `45^@` Latitude
    B
    The geographic poles
    C
    Two particles in air are separated by a certain distance ‘R’. Their masses are `M_1`and `M_2`and they have equal and similar charges ‘Q’. If the resultant force acting among them is zero, then the value of Q is
    D
    The magnetic poles
  • Our earth behaves as it has a powerful magnet within it. The value of magnetic field on the surface of earth is a few tenth of gauss (1G = 10^(-4) T) There are three elements of Earth’s magnetism (i) Angle of declination (ii) Angle of dip (iii) Horizontal component of Earth’s magnetic field. In the magnetic meridian of a certain place, the horizontal component of Earth’s magnetic field is 0.6 G and the dip angle is 53^@ . The value of vertical component of earth's magnetic field at this place is

    A
    0.8 G
    B
    0.6 G
    C
    1.0 G
    D
    2.0 G
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