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A short bar magnet is placed with its no...

A short bar magnet is placed with its north pole pointing south. The neutral point is `10cm` away from the centre of the magnet. If `H=0*4` gauss, calculate magnetic moment of the magnet.

Text Solution

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Here, `d=10cm=0*1m`, `H=0*4gauss=0*4xx10^-4T`, `M=?`
Neutral points in this case, lie on axial line of magnet, such that `(mu_0)/(4pi)(2M)/(d^3)=H`
`:. 10^-7xx(2M)/((0*1)^3)=0*4xx10^-4` or `M=0*2Am^-2`
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