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A short bar magnet is placed with its no...

A short bar magnet is placed with its north pole pointing north. If magnetic moment of magnet is `0*4Am^2` and horizontal component of earth's magnetic field is `0*4` gauss, what is the distance of neutral point from the centre of the magnet?

Text Solution

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Here, `M=0*4Am^2`, `H=0*4 gauss=0*4xx10^-4T, d=?`
When north pole is pointing north, `B=(mu_0)/(4pi)(M)/(d^3)=H`
`10^-7xx(0*4)/(d^3)=0*4xx10^-4`
`d^3=10^-3, d=10^-1m=10cm`
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