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The magnetic moment of a current carryin...

The magnetic moment of a current carrying loop is `2.1xx10^(-25) ampxxm^(2)`. The magnetic field at a point on its axis at a distance of `1 Å` is

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Here, `M=2*1xx10^(-25)Am^2`, `B=?`,
`d=1*0oversetoA=10^(-10)m`
The current loop is a short magnetic dipole,
`:. B=B_(ax ial)=(mu_0)/(4pi)xx(2M)/(d^3)`
`=(10^-7xx2xx2*1xx10^(-25))/((10^(-10))^3)=4*2xx10^-2tesla`
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