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What is the magnitude of the equatorial ...

What is the magnitude of the equatorial and axial fields due to a bar manget of length `5*0cm` at a distance of `50cm` from its mid-point? The magnetic moment of the bar magnet is `0*40Am^2`.

Text Solution

Verified by Experts

Here, `B_2=?, B_1=?, 2l=5*0cm`,
`l=2*5cm=2*5xx10^-2m`,
`d=50cm=0*5m, M=0*40Am^2`
`B_2=(mu_0)/(4pi)xx(M)/((d^2+l^2)^(3//2))=(mu_0)/(4pi)(M)/(d^3) ( :' l lt lt d)`
`=10^-7xx(0*40)/((0*5)^3)=3*2xx10^-7T`
`B_1=(mu_0)/(4pi)(2Md)/((d^2-l^2)^2)=(mu_0)/(2pi)(2M)/(d^3) ( :' l lt lt d)`
`B_1=10^-7xx(2xx0*40)/((0*5)^3)=6*4xx10^-7T`
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