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A short bar magnet of magnetic moment 0*...

A short bar magnet of magnetic moment `0*9JT^-1` is placed with its axis at `30^@` to a uniform magnetic field. It experiences a torque of `0*063J`. Calculate the magnitude of magnetic field. In which orientation will the bar magnet be in stable equilibrium in the magnetic field?

Text Solution

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Here, `M=0*JT^-1, theta=30^@`
`tau=0*063J, B=?`
`tau=MB sin theta, B=(tau)/(Msintheta)=(0*063)/(0*9xxsin30^@)`
`=0*14T`
For stable equilibrium, the magnetic moment `vecM` of magnet must be parallel to magnetic field `vecB`.
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