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A bar magnet when suspended horizontally...

A bar magnet when suspended horizontally and perpendicular to earth's field experiences a torque of `3xx10^-4Nm`. What is the magnetic moment of the magnet? Horizontal component of earth's magnetic field at that place is `0*4xx10^-4tesla`.

Text Solution

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Here, `theta=90^@`, `tau=3xx10^-4Nm`,
`M=?`, `B=0*4xx10^-4tesla`
As `tau=MB sin theta`
`:. M=(tau)/(B sintheta)=(3xx10^-4)/(0*4xx10^-4sin90^@)=7*5JT^-1`
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