Home
Class 12
PHYSICS
The true value of dip at a place is 45^@...

The true value of dip at a place is `45^@`. If the vertical plane carrying the needle is turned through `60^@` from the magnetic meridian, find the inclination of the needle (i.e. what will be the apparent value of dip)?

Text Solution

Verified by Experts

Here, `delta=45^@, theta=60^@, delta^'=?`
`tan delta^'=(tan delta)/(cos theta)=(tan 45^@)/(cos 60^@)=(1)/(1//2)=2`
`:. delta^'=tan^-1(2)=63*4^@`
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Conceptual Problems (d)|2 Videos
  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Very Short Answer Questions (a)|2 Videos
  • ELECTROSTATICS

    PRADEEP|Exercise ASSERTION-REASON TYPE QUESTIONS|2 Videos
  • OPTICS

    PRADEEP|Exercise Multiple choice questions|1 Videos

Similar Questions

Explore conceptually related problems

The true value of dip at a place is 30^(@) . The vertical plane carrying the needle is turned through 45^(@) from the magnetic meridian . Calculate the apparent value of dip .

The true value of dip at a place is 30^(@) . The vertical plane carrying needle is turned through 30^(@) from magnetic meridian . Calculate apparent value of angle of dip .

The true value of angle of dip at a place is 60^(@) . The apparent angle of dip , when a magnetic needle is rotated through 30^(@) from the magnetic meridian at the same place , is

The true dip at a place is 30^(@) . What is the apparent dip when the dip circle is turned 60^(@) out of the magnetic meridian ?

The true value of angle of dip at a place is 60^(@) , the apparent dip in a inclined at an angle of 30^(@) with magnetic meridian is

The true dip at a place is 30^@ . In what plane is the dip apparently 60^@ ?

The correct value of dip angle at a place is 45^(@) . If the dip circle is rotated by 45^(@) out of the meridian, then the tangent of the angle of apparent dip at the place is