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A magnetic needle free to rotate in a ve...

A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip down `60^@` with the horizotnal. The horizontal component of earth's magnetic field at the place is `0*4G`. Determine the magnitude of earth's magnetic field at the place.

Text Solution

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Here, `delta=60^@, H=0*4G, R=?`
From `H=Rcos delta`,
`R=(H)/(cos delta)=(0*4)/(cos 60^@)=(0*4)/(1//2)=0*8G`
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