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Horizontal component of earth's magnetiz...

Horizontal component of earth's magnetization at a place is `3*6xx10^-5T`, and dip of the place is `60^@N`. Obtain the vertical component and total intensity of earth's magnetization.

Text Solution

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Here, `H=3*6xx10^-5T, delta=60^@N`
`V=?, R=?`
From `tan delta=V/H`,
`V=Htandelta=(3*6xx10^-5)tan60^@`
`=3*6sqrt3xx10^-5T`
From `H=Rcosdelta`
`R=(H)/(cosdelta)=(3*6xx10^-5)/(cos 60^@)=(3*6xx10^-5)/(1//2)`
`=7*2xx10^-5T`
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