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In the magnetic meridian of a certain pl...

In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is `0*26G` and dip angle is `60^@`. What is the magnetic field of earth at this location?

Text Solution

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Here, `H=0*26G, delta=60^@, R=?`
As `H=Rcosdelta`
`:. R=(H)/(cos delta)=(0*26)/(cos60^@)=(0*26)/((1//2))=0*52G`
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