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If the horizontal component of earth's m...

If the horizontal component of earth's magnetic field at a place where the angle of dip is `60^@` is `0*4xx10^-4T`, calculate the vertical component and the resultant magnetic field at that place.

Text Solution

Verified by Experts

Here, `delta=60^@, H=0*4xx10^-4T`,
From `H=Rcos delta, R=(H)/(cos delta)=(0*4xx10^-4)/(cos60^@)`
`=0*8xx10^-4T`
`V=Rsindelta=0*8xx10^-4sin60^@`
`=0*8xx10^-4xxsqrt3/2=0*69xx10^-4T`
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