Home
Class 12
PHYSICS
At a certain place, a compass, needle po...

At a certain place, a compass, needle point `14^@` east of north. If dip at the place is `30^@` and horizontal component of earth's field is `0*32` gauss, what is earth's resultant field at that place?

Text Solution

Verified by Experts

Here, declination `theta=14^@` east.
`dip, delta30^@, H=0*32 gauss, R=?`
From `H=Rcosdelta`
`R=(H)/(cos delta)=(0*32)/(cos30^@)=(0*32)/(sqrt3//2)=0*37gauss`
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Conceptual Problems (d)|2 Videos

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Very Short Answer Questions (a)|2 Videos

  • ELECTROSTATICS

    PRADEEP|Exercise ASSERTION-REASON TYPE QUESTIONS|2 Videos

  • OPTICS

    PRADEEP|Exercise Multiple choice questions|1 Videos

Similar Questions

Explore conceptually related problems

At a certain place the angle of dip is 30^(@) and the horizontal component of earth's magnetic field is 0.50 oersted. The earth's total magnetic field is

Calculate earth's magnetic field at a place where angle of dip delta is 60^(@) and horizontal component of earth's magnetic field is 0.3 G

What is the angle of dip at a place where horizontal and vertical components of earth's field are equal?

At a certain place , horizontal component of earth's field is sqrt3 times the vertical component of earth's field . The angle of dip at this place is

The ratio of the vertical component to the horizontal component of earth's magnetic field at a place is 1 . What is the angle of dip at that place ?

At a certain place, the angle of dip is 30^(@) and the horizontal component of earth's magnetic field is 50muT . The total magnetic field (in muT ) of the earth at this place, is

The angle of dip at a certain place is 30^(@) . If the horizontal component of the earth's magnetic field is H, the intensity of the total magnetic field is