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Calculate the horizontal component of earth's magnetic field at place, where angle of dip is `30^@`. Given vertical component of earth's field at the place is `0*12sqrt3xx10^-4T`.

Text Solution

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Here, `H=? delta=30^@`,
`V=0*12sqrt3xx10^-4T`.
From `tandelta=V/H`
`H=(V)/(tan delta)=(0*12sqrt3xx10^-4)/(tan30^@)`
`=0*12sqrt3xx10^-4sqrt3=0*36xx10^-4T`
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