Home
Class 12
PHYSICS
A short bar magnet of magnetic moment 0*...

A short bar magnet of magnetic moment `0*5JT^-1` is placed with its magnetic axis in magnetic meridian, with its north pole pointing geographic north. A neutral point is obtained at a distance of `0*1m` from the centre of the magnet. Find the horizontal component of earth's magnetic field.

Text Solution

Verified by Experts

Here, `M=0*5JT^-1`, `d=0*1m`, `H=?`
As neutral point lies on equatorial line of magnet,
`:. H=(mu_0)/(4pi)(M)/(d^3)=(10^-7xx0*5)/((0*1)^3)=0*5xx10^-4T`
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Conceptual Problems (d)|2 Videos

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Very Short Answer Questions (a)|2 Videos

  • ELECTROSTATICS

    PRADEEP|Exercise ASSERTION-REASON TYPE QUESTIONS|2 Videos

  • OPTICS

    PRADEEP|Exercise Multiple choice questions|1 Videos

Similar Questions

Explore conceptually related problems

A short bar magnet of magnetic moment 0*5JT^-1 is placed with its magnetic axis in the magnetic meridian, with its north pole pointing geographic north. A neutral point is obtained at a distance of 0*1m from the centre of the magnet. Find the horizontal component of earth's magnetic field.

A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the centre of the magnet. Calculate the horizontal component of earth’s magnetic field.

A short bar magnet of magnetic moment 1.2Am^(2) is placed in the magnetic meridian with its south pole pointing the north. If a neutral point is found at a distance of 20cm from the centre of the magnet, the value of the horizontal component of the earth's magnetic field is

A 30 cm long bar magnet is placed in the magnetic meridian with its north pole pointing south. The neutral point is obtained at a distance of 40 cm from the centre of the magnet. Pole strength of the magnet is (The horizontal component of earth’s magnetic field is 0.34 Gauss)

A bar magnet of length 10cm is placed in the magnetic meridian with its north pole pointing towards the geographical north. A neutral point is obtained at a distance of 12cm from the centre of the magnet. Find the magnetic moment of the magnet, when H=0*34 gauss .

A bar magnet is placed with its north pole towards geographic north. The neutral point

A short bar magnet is placed in the magnetic meridian with its north pole pointing towards geographical south. A neutral point is found at a distance of 30 cm from the centre of the magnet. If the horizontal component of earth's field is 0.4G , calculate the magnetic moment of the magnet .

A bar magnet 30cm long is placed in magnetic meridian with its north pole pointing south. The neutral point is observed at a distance of 30cm from its centre. Calculate the pole strength of the magnet. Given horizontal component of earth's field is 0*34G .

A short bar magnet is placed in magnetic meridian with its north pole pointing toward south: Its magnetic moment is 2Am^(2) . Neutral point is obtained 10cm from centre of magnet toward north. Calculate horizontal component of earth's magnetic field.

A bar magnet of length 14 cm is placed in the magnetic meridian with its north pole pointing towards the geographic north pole. A neutral point is obtained at a distance of 18 cm from the center of the magnet. If B_(H)=0.4 G, the magnetic moment of the magnet is (1G = 10 ^(-4) T)