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An electron in an atom revolves around t...

An electron in an atom revolves around the nucleus in an orbit of radius `0*5 Å`. Calculate the equivalent magnetic moment if the frequency of revolution of electron is `6*8xx10^9MHz`.

Text Solution

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Here, `r=0*53 Å=0*53xx10^(-10)m`,
`M=?`
`v=6*8xx10^9MHz=6*8xx10^(15)Hz`
`M=iA=evxxpir^2`
`=1*6xx10^(-19)xx6*8xx10^(15)xx3*14(0*53xx10^(-10))^2`
`M=9*3xx10^(-24)Am^2`
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