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When temperature of a ferromagnetic mate...

When temperature of a ferromagnetic material is increased by 10%, what is the percentage change in its magnetic susceptibility?

Text Solution

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According to Curie's Law
`chi_m prop 1/T`
`:. (chi_(m2))/(chi_(m1))=T_1/T_2=(100)/(100+10)=10/11`
`chi_(m2)=10/11chi_(m1)=10/11xx100%chi_(m1)`
`=90.9%chi_(m1)`
`:.` Decrease in magnetic susceptibility
`=100-90*9`
`=9*1%`
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