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How will the magnetic field induction at...

How will the magnetic field induction at the centre of a circular coil carrying current change, if the current through the coil is doubled and the radius of the coil is halved?

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Magnetic field induction at the centre of the circular coil carrying current is
`B=(mu_0)/(4pi)(2pinI)/(r)` i.e. `Bpropn/r`
`:. B^'/B=(2n)/((r//2))xxr/n=4` or `B^'=4B`
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