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A galvanomter of resistance 50Omega is s...

A galvanomter of resistance `50Omega` is shunted by a resistance of `5Omega`. What fraction of the main current passes through the galvanometer? Through the shunt?

Text Solution

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Fraction of current passing through galvanometer `=(i_g)/(i)=(S)/(G+S)=(5)/(50+5)=(1)/(11)`
Fraction of current passing through shunt
`=(i_s)/(i)=(i-i_g)/(i)=1-(i_g)/(i)=1-1/11=10/11`
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