Home
Class 12
PHYSICS
A compass needle, free to turn in a vert...

A compass needle, free to turn in a vertical plane orients itself with its axis vertical at a certain place on the earth. Find out the values of (i) Horizontal component of earth's magnetic field and (ii) angle of dip at that place.

Text Solution

Verified by Experts

(i) At the given place total earth's magnetic field B is along the vertical diretion. Therefore, the horizontal component of earth's magnetic field
`B_H=B cos 90^@=0`.
(ii) Angle of dip at that place=angle between the axis of needle with the horizontal line in magnetic meridian`=90^@`.
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Conceptual Problems (d)|2 Videos
  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Very Short Answer Questions (a)|2 Videos
  • ELECTROSTATICS

    PRADEEP|Exercise ASSERTION-REASON TYPE QUESTIONS|2 Videos
  • OPTICS

    PRADEEP|Exercise Multiple choice questions|1 Videos

Similar Questions

Explore conceptually related problems

The vertical component of the earth’s magnetic field at a place is 0.24sqrt3xx10^-4 T Find out the value of horizontal component of the earth’s magnetic field, if angle of dip at that place is 30^@ .

The ratio of the vertical component to the horizontal component of earth's magnetic field at a place is 1 . What is the angle of dip at that place ?

What is the angle of dip at a given place on the earth if both vertical and horizontal components of the earth's magnetic field are equal ?

At a certain place, the horizontal component of earth's magnetic field is sqrt(3) times the vertical component. The angle of dip at that place is