Home
Class 12
PHYSICS
Two moving coil meters M1 and M2 have th...

Two moving coil meters `M_1` and `M_2` have the following particulars:
`R_1=10Omega`, `N_1=30`, `A_1=3*6xx10^-3m^2`, `B_1=0*25T`,
`R_2=14Omega`, `N_2=42`, `A_2=1*8xx10^-3m^2`, `B_2=0*50T`
(The spring constants are identical for the two metres). Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of `M_2` and `M_1`.

Text Solution

AI Generated Solution

To solve the problem, we need to determine the ratio of current sensitivity and voltage sensitivity of two moving coil meters, \( M_1 \) and \( M_2 \). ### Given Data: - For meter \( M_1 \): - \( R_1 = 10 \, \Omega \) - \( N_1 = 30 \) - \( A_1 = 3.6 \times 10^{-3} \, m^2 \) - \( B_1 = 0.25 \, T \) ...
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Conceptual Problems (d)|2 Videos
  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Very Short Answer Questions (a)|2 Videos
  • ELECTROSTATICS

    PRADEEP|Exercise ASSERTION-REASON TYPE QUESTIONS|2 Videos
  • OPTICS

    PRADEEP|Exercise Multiple choice questions|1 Videos

Similar Questions

Explore conceptually related problems

Two moving coil metres M_(1) and M_(2) have the following particular R_(1) =10Omega, N_(1) =30, A_(1) = 3.6 xx 10^(-3) m^(2), B_(1) =0.25 T, R_(2) = 14Omega , N_(2) =42, A_(2) = 1.8 xx 10^(-3) m^(2), B_(2) =0.50 T The spring constants are identical for the two metres. What is the ratio of current sensitivity and voltage sensitivity of M_(2)" to" M_(1)?

Two moving coil meters, M_(1) and M_(2) have following particulars : R_(1)=10Omega,N_(1)=30,A_(1) =3.6xx10^(-3)m^(2),B_(1)=0.25T R_(2)=10Omega,N_(2)=42,A_(2) =1.8xx10^(-3)m^(2),B_(2)=0.50T ( The spring constants are identical for two meters ) . The ration of (i) current sensitivity (ii) voltage sensitivity of M_(2) and M_(1) is

Compare the current sensitivity and voltage sensitivity of the following moving coil galvanometers: Meters A : n=30, A=1*5xx10^-3m^2 , B=0*25T, R=20Omega Meter B: n=35, A=2*0xx10^-3m^2 , B=0*25T, R=30Omega . You are given that the springs in the two meters have the same torsional constants.

A moving coil meter has the following particulars: Numbers of turns, n=24 , Area of coil, A=2*0xx10^-3m^2 , magnetic field strength, B=0*20T . Resistance of the coil, R=14Omega . (a) Indicate a simple way to increase the current sensitivity of the meter by 25% . (It is not easy to change A or B). (b) If in so doing, the resistance of the coil increases by 7Omega , is the voltage sensitivity of the modified meter greater or lesser than the original meter?

A moving coil meter has the following particulars. Number of turns, N=20 , Area of the coil, A=2*0xx10^-3m^2 , Magnetic field strength, B=0*20T , Resistance of the coil, R=12Omega . (a) Indicate a simple way to increase the current sensitivity of the meter by 20% (It is not easy to change A or B). (b) If in so doing, the resistance of the coil increases to 18Omega , is the voltage sensitivity of the modified meter greater or lesser than the original meter?

Two moving coil galvanometers A and B have rectangular coil of 100 turns each. The area of coil of galvanometers A and B are 2 xx 10^(-4) m^(2) " and " 6 xx 10^(-4) m^(2) respectively. Calculate the ratio of current sensitivity of A to B if coils in both salvanometers are kept in a radial horizontal magnetic field of 0.2 T and the torsional constant of hair springs are also same.

The coil of moving coil galvanometer has an effective area 6xx10^-2m^2 . It is suspended in a magnetic field of 3xx10^-2Wbm^-2 . If the torsional constant of the suspension fibre is 5xx10^-9Nmdeg^-1 , finds its current sensitivity in degree per micro-ampere.

Two particles A_1 and B_2 of masses m_1 and m_2 (m_1 gt m_2) have the same de Broglie wavelength . Then