Home
Class 12
PHYSICS
If the bar magnet in the above problem i...

If the bar magnet in the above problem is turned around by `180^@`, where will the new null points be located?

Text Solution

Verified by Experts

When the bar magnet is turned through `180^@`, neutral points would lie on equatorial line, so that
`B_2=(mu_0)/(4pi)(M)/(d_2^3)=H` …(i)
In the previous question, `B_1=(mu_0)/(4pi)(2M)/(d_1^3)=H` …(ii)
From (i) and (ii), `(mu_0)/(4pi)(M)/(d_2^3)=(mu_0)/(4pi)(2M)/(d_1^3) :. d_2^3=d_1^3/2=((14)^3)/(2)`
`d_2=(14)/(2^(1//3)=11*1cm`
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Conceptual Problems (d)|2 Videos

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Very Short Answer Questions (a)|2 Videos

  • ELECTROSTATICS

    PRADEEP|Exercise ASSERTION-REASON TYPE QUESTIONS|2 Videos

  • OPTICS

    PRADEEP|Exercise Multiple choice questions|1 Videos

Similar Questions

Explore conceptually related problems

In the above problem No. 96, if angle turned is 270^(@) then the change in velocity will be

When N- pole of the given bar magnet is placed on a table pointing geographic north,the null points are formed due to the superposition of the magnetic field of the "bar" magnet and the earth's magnetic field. The two null points are located

When the N -pole of a bar magnet points towards the south and S-pole towards the north, the null points are at the

If the value of potential gradient on potentiometer wire is decreased, then the new null point will be obtained at

Where are the magnetic poles of the earth located?

A short bar magnet is placed in a horizontal plane with its axis in the magnetic merdian . Null points are found on its equitorial line (i.e., its normal bisector) at 12.5 G and the angle of dip is zero. (i) What is the total magnetic field at points on the axis of the magnet located by the same distance (12.5 cm) as the null-points from the centre? (ii) Locate the null points when the magnet is turned around by 180^(@) . Assume that the length of the magnet is negligible as compared to the distance of the null-point from the centre of the magnet.