A bar magnet of magnetic moment M and moment of inertia I (about centre, perpendicular to length) is cut into two equal pieces, perpendicular to length. Let T be the period of oscillation of the original magnet about an axis through the mid point, perpendicular to length, in a magnetic field `vecB`. What would be the similar period `T^'` for each piece?

Explanation

To solve the problem, we need to analyze the situation step by step.

### Step 1: Understand the original period of oscillation
The period of oscillation \( T \) of the original bar magnet is given by the formula:
\[ T = 2\pi \sqrt{\frac{I}{MB}} \]
where \( I \) is the moment of inertia, \( M \) is the magnetic moment, and \( B \) is the magnetic field.
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