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Two wires CO and OA carry equal currents...

Two wires CO and OA carry equal currents I as shown in figure. One end of both the wires extends to infinity. Given `/_AOC=theta`. What is the magnitude of magnetic field induction at a point P at a distance r from O lying on the bisector of angle `theta`.

Text Solution

Verified by Experts

`a=r sin (theta//2)`
Magnetic field induction at P due to current through CO and OA is
`B=2[(mu_0)/(4pi)I/a[sin(90-theta//2)+sin 90^@]]=(mu_0)/(2pi)(I(1+cos theta//2))/(r sin theta//2)`
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Knowledge Check

  • Two wires AO and OC carry equal currents i as shown in Fig. One end of both the wires extends to infinity. Angle AOC is alpha . The magnitude of magnetic field is point P on the bisector of these two wires at a distance r from point O is

    A
    `(mu_0)/(2pi) i/r cot ((alpha)/2)`
    B
    `(mu_0)/(4pi) i/r cot ((alpha)/2)`
    C
    `(mu_0)/(2pi) i/r (1+cos(alpha)/2)/(sin(alpha/2))`
    D
    `(mu_0)/(4pi) i/r ((alpha)/2)`
  • A current carrying wire is bent in the L shapes as shown in figure. The length of both arms extend to infinity. Then, the magnetic field at O is-

    A
    zero
    B
    `mu_(0)I//2pir`
    C
    `(mu_(0)I)/(2pir)(1+1/(sqrt(2)))`
    D
    `(mu_(0)I)/(4pir)(1+1/(sqrt(2)))`
  • An infinitely long wire carrying current I is along Y-axis such taht its one end is at point A(0,b) while the wire extends upto +oo . The magnitude of magnetic field strength at point (a,0) is

    A
    `(mu_0I)/(4pia)(1+b/(sqrt(a^2+b^2)))`
    B
    `(mu_0I)/(4pia)(1-b/(sqrt(a^2+b^2)))`
    C
    `(mu_0I)/(4pia)(b/(sqrt(a^2+b^2)))`
    D
    none of these
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