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An iron sample having mass 8*4kg is repe...

An iron sample having mass `8*4kg` is repeatedly taken over cycles of magnetisation and demagnetisation at a frequency of `50cps`. It is found that energy of `3*2xx10^4J` is dissipated as heat in the sample in 30 minutes. If the density of iron is `7200kg//m^3`, calculate the value of energy dissipated per unit volume per cycle in the iron sample.

Text Solution

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Here, `m=8*4kg`, `v=50c//s`, `rho=7200kgm^-3`
Volume `=m/rho=(8*4)/(7200)=1*167xx10^-3m^3`,
Energy dissipated in 30 minutes `=3*2xx10^4J`
Energy dissipated/sec `=(3*2xx10^4)/(30xx60)=17*78Js^-1`
Energy dissipated/volume/cycle `=(17*78)/(1*167xx10^-3xx50)=304*7Jm^-3cycl e^-1`
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