The electron of hydrogen atom moves along a circular path of radius `0*5xx10^(-10)m` (i) with a speed of `4*0xx10^6ms^-1`. (ii) with a frequency `6*8xx10^(15)Hz`. Calculate the magnetic field produced at the centre of the circular path.
`(e=1*6xx10^(-19)C)`.

Answer

`25*6T`, `13*4T`

Explanation

(i) `T=2pi r//v` and `i=e/T=(ev)/(2pir)`
(ii) `i=ev`
Now use, `B=(mu_0)/(4pi)(2pi i)/(r)=(mu_0)/(4pi)(2pi)/(r)ev`