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A solenoid of length 0*20m, having 120 t...

A solenoid of length `0*20m`, having `120` turns carries a current of `2*5A`. Find the magnetic field: (a) in the interior of the solenoid, (b) at one end of the solenoid. Given `mu_0=4pixx10^-7` S.I. units.

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The correct Answer is:
(a) `1*885xx10^-3T` (b) `0*9425xx10^-3T`
(i) `B=mu_0(NI)/(l)`,
Here, `l=0*20m`, `N=120`, `I=2*5A`
(ii) `B=(mu_0NI)/(2l)`
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