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An electron enters electric field of 10^...

An electron enters electric field of `10^4V//m` perpendicular to the field with a velocity of `10^7m//s`. Find the vertical displacement of electron after 2 milliseconds. Mass of electron `=9*1xx10^(-31)kg`, charge on electron `=1*6xx10^(-19)C`.

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Verified by Experts

The correct Answer is:
`3*51xx10^9m`
`y=1/2at^2=1/2(Ee)/(m)t^2`
`=(10^4xx(1*6xx10^(-19))xx(2xx10^-3)^2)/(2xx9*1xx10^(-31))`
`=3*51xx10^9m`
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