A chamber is maintained a uniform magnetic field of `5xx10^-3T`. An electron with a speed of `5xx10^7ms^-1` enters the chamber in a direction normal to the field. Calculate (i) radius of the path (ii) frequency of revolution of the electron.
Charge of electron `=1*6xx10^(-19)C`,
Mass of electron `=9*1xx10^(-31)kg`

Answer

(i) `5*7cm` (ii) `1*4xx10^8Hz`

Explanation

Here, `B=5xx10^-3T`, `v=5xx10^7ms^-1`,
`e=1*6xx10^(-19)C`, `m=9*1xx10^(-31)kg`
(i) Radius of the circular path,
`r=(mv)/(Be)=((9*1xx10^(-31))xx(5xx10^7))/((5xx10^-3)xx(1*6xx10^(-19)))`
`=5*7xx10^-2m`
`=5*7cm`
(ii) Frequency of revolution,
`v=(eB)/(2pim)=((1*6xx10^(-19))xx(5xx10^-3))/(2xx3*14xx(9*1xx10^(-31))`
`=1*4xx10^8Hz`