An infinite long straight conductor XY is carrying a current of `10A`. An electron is moving with a speed of `10^5m^-1` parallel to the conductor in air from point A to B, as shown in figure. The perpendicular distance between the electron and the conductor XY is `20cm`. Calculate the magnitude of the force experienced by the electron. Write the direction of this force.

Answer

`1*6xx10^(-19)N`, in the plane of paper away from XY

Explanation

`B=(mu_0)/(4pi)(2I)/(r)=(10^-7xx2xx10)/(0*20)=10^-5T`
It is acting perpendicular to the plane of paper upwards.
`F=qvBsin theta`
`=1*6xx10^(-19)xx10^5xx10^-5xxsin90^@`
`=1*6xx10^(-19)N`
The direction of `vecF[=q(vecvxxvecB)]` is the plane of paper away from XY.