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A circular coil of 200 turns, radius 5cm...

A circular coil of 200 turns, radius `5cm` carries a current of `2*5A`. It is suspended vertically in a uniform horizontal magnetic field of `0*25T`, with the plane of the coil making an angle of `60^@` with the field lines. Calculate the magnitude of the torque that must be applied on it to prevent it from turning.

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Verified by Experts

The correct Answer is:
`0*49 Nm`
`tau=nIBAsin alpha`, Here, `n=200`, `I=2*5A`,
`B=0*25T`, `alpha=90^@-60^@=30^@`,
`A=pir^2=22/7xx(0*05)^2m^2`
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