The coil of moving coil galvanometer has an effective area `6xx10^-2m^2`. It is suspended in a magnetic field of `3xx10^-2Wbm^-2`. If the torsional constant of the suspension fibre is `5xx10^-9Nmdeg^-1`, finds its current sensitivity in degree per micro-ampere.

Answer

`0*36 deg//mu_A`

Explanation

Here, `n=1`, `A=6xx10^-2m^2`,
`B=3xx10^-2Wbm^-2`, `k=5xx10^-9Nmdeg^-1`
Current sensitivity `I_s=theta/I=(nBA)/(k)`
`=(1xx(3xx10^-2)xx(6xx10^-2))/(5xx10^-9)`
`=3*6xx10^5degA^-1`
`=(3*6xx10^5)/(10^6)deg//muA`
`=0*36deg//muA`