An ammeter gives full scale deflection with a deflection for a current of `0*05A`. Calculate the length of shunt wire required to convert the galvanometer into an ammeter of range 0 to `5A`. The diameter of the shunt wire is `2mm` and its resistivity is `5xx10^-7Omegam`.

Answer

`3*174m` in parallel

Explanation

`S=(I_gG)/(I-I_g)=(1xxG)/(10-1)=G/9Omega`,
Resistance of ammeter formed
`R_p=(SxxG)/(G+S)=((G//9)xxG)/(G+G//9)=(G//9)/(10//9)=G/10`
`:. R_p/S=(G//10)/(G//9)=9/10`