Home
Class 12
PHYSICS
The resistance of a pivoted type galvano...

The resistance of a pivoted type galvanometer is `8Omega` and current for full scale deflection on it is `0*01A`. This galvanometer is to be converted into an ammeter of `5A` range. The only shunt available is `0*02Omega`. Find the value of R to be connected in series with the galvanometer coil, figure.

Text Solution

Verified by Experts

The correct Answer is:
`1*98Omega`
`I_g(G+R)=(I-I_g)S`
or `0*01(8+R)=(5-0*01)0*02=4*99xx0*02`
or `R=(4.99xx0.02)/(0.01)-8=9.98-8`
`=1.98Omega`
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Test Your Grip (a)|1 Videos

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Test Your Grip (c)|1 Videos

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Value Based Questions|2 Videos

  • ELECTROSTATICS

    PRADEEP|Exercise ASSERTION-REASON TYPE QUESTIONS|2 Videos

  • OPTICS

    PRADEEP|Exercise Multiple choice questions|1 Videos

Similar Questions

Explore conceptually related problems

The resistance of galvanometer coil is 0.1 Komega . The current for full scale deflection is 100 mu A. The value of the resistance put in series to convert it into a voltmeter of range 0.1 volt is –

A moving coild galvanometer of resistance 20 Omega gives a full scale deflection when a current of 1mA is passed through it. It is to be converted into an ammeter reading 20A. But the resistance of the only shunt available is 0.005Omega . What resistance should be connected in series with the galvanometer coil?

A galvanometer of resistance 99 Omega requires 5 mA current for full scale deflection. It can be converted into an ammeter of range 0.5 A by connecting a shunt resistance of

The resistance of a moving coil galvanometer is 20Omega . It requires 0.01 A current for full - scale deflection. The value of resistance to convert it into a voltmeter of the range 20 V will be

The resistance of a moving coil galvanometer is 20 Omega . If requires 0.01 ampere current for full scale deflection. The value of resistance to convert in into a voltmeter of range 20 volt will be

The resistance of a moving coil galvanometer is 20Omega . It requires 0.01A current for full scale deflection calculate the value of resistan ce required to convert it into a voltmeter of range 20 volt.

A galvanometer has a resistance of 118Omega and gives full scale deflection for a current of 50 m A. if it is required to convert into an ammeter of range 3A, the shunt resistance should be

A galvanometer coil has a resistance of 50 Omega and the meter shows full scale deflection for a current of 5 mA. This galvanometer is converted into voltmeter of range 0-20 by connecting

A moving coil galvanometer of resistance 20 Omega gives a full scale deflection when a current of 1mA is passed through it. It is to be converted into an ammeter reading 20 A on full scale. But the shunt of 0.005 Omega only is available. What resistance should be connected in series with the galvanometer coil?

PRADEEP-MAGNETIC EFFECT OF CURRENT AND MAGNETISM-Exercise
  1. A galvanometer can be converted into a voltmeter of certain range by c...

    Text Solution

    |

  2. The scale of galvanometer is divided into 150 equal divisions. The gal...

    Text Solution

    |

  3. The resistance of a pivoted type galvanometer is 8Omega and current fo...

    Text Solution

    |

  4. The voltmeter V in the figure. Reads 117V and the ammeter A reads 0*13...

    Text Solution

    |

  5. In a galvanometer there is a deflection of 10 divisions per 50 mA. The...

    Text Solution

    |

  6. Two very long straight wires P and Q carry currents of 10A and 20A res...

    Text Solution

    |

  7. A moving coil meter has the following particulars. Number of turns, N=...

    Text Solution

    |

  8. A proton (charge =1*6xx10^(-19)C, mass m=1*67xx10^(-27)kg) is shot wit...

    Text Solution

    |

  9. In figure, a long wire AB is placed on a table. A wire CD 10cm long, i...

    Text Solution

    |

  10. Find the force on the conductor carrying current I1 as shown in figure...

    Text Solution

    |

  11. A bar magnet of magnetic moment of 5*0Am^2 has poles 20cm apart. Calcu...

    Text Solution

    |

  12. A steel wire of length l has a magnetic moment M. It is bent into a se...

    Text Solution

    |

  13. Two thin bar magnets of pole strengths 25Am and 48Am respectively and ...

    Text Solution

    |

  14. The force between two magnetic poles in air is 9*604mN. If one pole is...

    Text Solution

    |

  15. Two identical magnets with a length 10cm and weights 50gf each are arr...

    Text Solution

    |

  16. A bar magnet of length 10cm has a pole strength of 10Am. Calculate the...

    Text Solution

    |

  17. Two small magnets are placed horizontally perpendicular to magnetic me...

    Text Solution

    |

  18. The earth's field, it is claimed, roughly approximates the field due t...

    Text Solution

    |

  19. The magnetic moment of the assumed dipole at the earth's centre is 8.0...

    Text Solution

    |

  20. The magnetic field at a point on the magnetic equator is found to be 3...

    Text Solution

    |