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The magnetic dipole moment of earth is 6...

The magnetic dipole moment of earth is `6*4xx10^(21)Am^2`. If we consider it to be due to a current loop wound around the magnetic equator of the earth, then what should be the magnitude of the current? Take earth to be a sphere of radius `6400km`.

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The correct Answer is:
`5xx10^7A`
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PRADEEP-MAGNETIC EFFECT OF CURRENT AND MAGNETISM-Exercise
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  2. A current of 5A is flowing through a 10 turn circular coil of radius 7...

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  3. The magnetic dipole moment of earth is 6*4xx10^(21)Am^2. If we conside...

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  4. A circular coil of 300 turns and diameter 14cm carries a current of 15...

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  5. A magnetised needle of magnetic moment 4*8xx10^-2JT^-1 is placed at 30...

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  6. A bar magnet placed in a uniform magnetic field of strength 0*3T with ...

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  7. Calculate the work done in rotating a magnet of magnetic moment 3*0JT^...

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  8. A bar magnet is suspended in a region where it is acted upon by two ma...

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  9. Two magnects of magnetic moments M and Msqrt3 are joined to form a cro...

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  10. A short bar magnet placed with its axis at 30^@ with a uniform externa...

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  11. A circular coil of 100 turns and having a radius of 0*05m carries a cu...

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  12. A magnetic needle lying parallel to a magnetic field needs 2J work to ...

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  13. A vertical coil of sides 5cm xx 2cm has 10 turns and carries 2A curren...

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  14. A bar magnet with poles sqrt3cm apart and pole strength 14*4Am rests w...

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  15. A magnetic dipole is under the influence of two magnetic fields. The a...

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  16. Vertical component of earth's magnetic field at a place is sqrt3 times...

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  17. The declination at a place is 15^@ west of north. In which direction s...

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  18. If the horizontal component of earth's magnetic field at a place is 0*...

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  19. A dip circle shows an apparent dip of 60^@ at a place where true dip i...

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  20. A compass needle whose magnetic moment is 60Am^2 points geographic nor...

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