Calculate the work done in rotating a magnet of magnetic moment `3*0JT^-1` through an angle of `60^@` from its position along a magnetic field of strength `0*34xx10^-4T`.

Answer

`5*1xx10^-5T`

Explanation

Here, `W=?`, `M=3*0JT^-1`, `theta_2=60^@`, `theta_1=0^@`
`B=0*34xx10^-4T`
`W=-MB(costheta_2-costheta_1)`
`=-3*0xx0*34xx10^-4(cos60^@-cos0^@)`
`=5*1xx10^-5J`