If the horizontal component of earth's magnetic field at a place is `0*4xx10^-4T` where dip is `60^@`, what are the values of vertical component and resultant magnetic field?

Answer

`0*69xx10^-4T`; `0*8xx10^-4T`

Explanation

Here, `H=0*4xx10^-4T`, `delta=60^@`, `V=?`, `R=?`
`V=H tan delta=0*4xx10^-4 tan60^@`
`=0*4sqrt3xx10^-4T=0*69xx10^-4T`
`R=(H)/(cos delta)=(0*4xx10^-4)/(cos60^@)=0*8xx10^-4T`