The true dip at a place is `30^@`. In what plane is the dip apparently `60^@`?

Answer

`70*5`

Explanation

Here, `delta=30^@` and `delta^'=60^@`, `theta=?`
`tan delta=V/H` and `tan delta^'=V/H^'=(V)/(Hcostheta)`
`tan delta^'=(tan delta^')/(cos theta)`
`:. cos theta= (theta delta)/(tan delta^')=(tan30^@)/(tan60^@)=(1)/(sqrt3.sqrt3)=1/3`
`cos theta=0*3333`
`:. theta=70*5^@`