An electron is revolving in a hydrogen atom in a circular orbit of radius `4Å` making `10^(15)rps`. What is the magnetic moment associated with this electron?

Answer

`8*038xx10^(-23)Am^2`

Explanation

Here, `r=4Å=4xx10^(-10)m, v=10^(15)rps`,
`M=?`
`M=IA=(ev)pir^2`
`=(1*6xx10^(-19)xx10^(15))xx3*14(4xx10^(-10))^2`
`=8*038xx10^(-23)Am^2`