An electron in an atom revolves around the nucleus in an orbit of radius `0*53Å`. Calculate the equivalent magnetic moment, if the frequency of revolution of electron is `6*8xx10^9MHz`.

Answer

`9*6xx10^(-24)Am^2`

Explanation

Here, `r=0*53Å=0*53xx10^(-10)m`
`v=6*8xx10^9MHz=6*8xx10^(15)Hz`, `M=?`
If e is charge on electron, then the equivalent current, `I=e/T=ev`
`M=IA=ev(pir^2)`
`=1*6xx10^(-19)xx6*8xx10^(15)xx3*14(0*53xx10^(-10))^2`
`=9*6xx10^(-24)Am^2`