A bar magnet made of steel has a magnetic moment of `2.5 A m^2` and mass of `6.6 xx 10^(-5) kg`. If the density of steel is `7.9 xx 10^3 kg m^(-3)`, find the intensity of magnetization of the magnet.

Answer

`3*0xx10^6Am^-1`

Explanation

Here, `M=2*5Am^2`, `m=6*6g=6*6xx10^-3kg`
`rho=7*9xx10^3kg//m^3`,
`V=m/rho=(6*6xx10^-3)/(7*9xx10^3)=0*835xx10^-6m^3`
`I=M/V=(2*5)/(0*835xx10^-6)=3*0xx10^6Am^-1`