The magnetic field `B` and the magnetic intensity `H` in a material are found to be `1.6 T and 1000 A m^(-1)` respectively. Calculate the relative permeability `mu`, and the susceptibility `chi` of the material.

Answer

`1*3xx10^3` each

Explanation

`mu=B/H=(1*6)/(1000)=1*6xx10^-3TmA^-1`
`mu_r=(mu)/(mu_0)=(1*6xx10^-3)/(4pixx10^-7)=1*3xx10^3`
`chi_m=mu_r-1=1*3xx10^3-1=1*3xx10^3`