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A current loop consists of two identical semicircular parts each of radius R, one lying in the x-y plane and the other in x-y plane. If the current in the loop is i, the resultant magnetic field due to two semicircular parts at their common centre is

A

`(mu_0i)/(2sqrt2R)`

B

`(mu_0i)/(2R)`

C

`(mu_0i)/(4R)`

D

`(mu_0i)/(sqrt2R)`

Text Solution

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The correct Answer is:
To solve the problem of finding the resultant magnetic field at the common center of two identical semicircular current loops, we will follow these steps: ### Step 1: Understanding the Configuration We have two semicircular loops, each of radius \( R \). One loop lies in the x-y plane, and the other lies in the x-z plane. The current \( i \) flows through both loops. ### Step 2: Determine the Magnetic Field due to Each Semicircular Loop Using the formula for the magnetic field at the center of a semicircular loop of radius \( R \) carrying a current \( i \): \[ B = \frac{\mu_0 i}{4R} \] where \( \mu_0 \) is the permeability of free space. ### Step 3: Calculate the Magnetic Field Direction 1. **For the semicircular loop in the x-y plane (B1)**: - By the right-hand rule, if the current flows counterclockwise when viewed from above, the magnetic field \( B_1 \) will point in the positive z-direction. - Therefore, \( B_1 = \frac{\mu_0 i}{4R} \hat{k} \). 2. **For the semicircular loop in the x-z plane (B2)**: - Again, using the right-hand rule, if the current flows counterclockwise when viewed from the positive y-axis, the magnetic field \( B_2 \) will point in the negative y-direction. - Therefore, \( B_2 = -\frac{\mu_0 i}{4R} \hat{j} \). ### Step 4: Resultant Magnetic Field Calculation The resultant magnetic field \( B_{net} \) at the common center is the vector sum of \( B_1 \) and \( B_2 \): \[ B_{net} = B_1 + B_2 = \frac{\mu_0 i}{4R} \hat{k} - \frac{\mu_0 i}{4R} \hat{j} \] ### Step 5: Final Result Thus, the resultant magnetic field at the common center due to the two semicircular parts is: \[ B_{net} = \frac{\mu_0 i}{4R} \hat{k} - \frac{\mu_0 i}{4R} \hat{j} \]

To solve the problem of finding the resultant magnetic field at the common center of two identical semicircular current loops, we will follow these steps: ### Step 1: Understanding the Configuration We have two semicircular loops, each of radius \( R \). One loop lies in the x-y plane, and the other lies in the x-z plane. The current \( i \) flows through both loops. ### Step 2: Determine the Magnetic Field due to Each Semicircular Loop Using the formula for the magnetic field at the center of a semicircular loop of radius \( R \) carrying a current \( i \): \[ ...
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