A recantagular coil of length `0.12 m` and width `0.1 m` having 50 turns of wire is suspended vertically in unifrom magnetic field of srenght 0.2 `Weber//m^(2)`. The coil carres a current of 2 A. If the plane of the coil is inclined at an angl,e of `30^(@)` with the direction of the feld the torque required to keep the coil in stable equilibrium will be

Options

A. `0*12Nm`
B. `0*15Nm`
C. `0*20Nm`
D. `0*24Nm`

Explanation

Here, `l=0*12m`, `b=0*1m`, `n=50`,
`B=0*2Wm^-2`, `I=2A`
Refer to figure, angle between `vecM` and `vecB` is `theta=90^@-30^@=60^@`
Torque `=nIAB sin theta=nI lb B sin theta`
`=50xx2xx0*12xx0*1xx0*2xxsin 60^@`
`=12sqrt3xx10^-2Nm`
`=0*20748Nm`