A galvanometer of resistance `25Omega` is connected to a battery of 2 volt along with a resistance in series. When the value of this resistance is `3000Omega`, a full scale deflection of 30 units is obtained in the galvanometer. In order to reduce this deflection to 20 units, the resistance in series will be

Options

A. `4514Omega`
B. `5413Omega`
C. `2000Omega`
D. `6000Omega`

Explanation

To solve the problem step by step, we will analyze the given information and apply the relevant formulas.

### Step 1: Understand the given values
- Resistance of the galvanometer \( G = 25 \, \Omega \)
- Voltage of the battery \( V = 2 \, \text{V} \)
- Series resistance \( R = 3000 \, \Omega \)
- Full-scale deflection current for 30 units \( I_{G30} \)

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