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A galvanometer with resistance 1000Omega...

A galvanometer with resistance `1000Omega` gives full scale deflection at `0*1mA`. What value of resistance should be added to `1000Omega` to increase its current range `10A`.

A

`0*01Omega` in series

B

`0*01Omega` in parallel

C

`0*10Omega` in series

D

`0*10Omega` in parallel

Text Solution

Verified by Experts

The correct Answer is:
B

Here, `G=1000Omega`, `I_g=0*1mA=10^-4A`,
`I=10A`
`S=(I_gG)/(I-I_g)=(10^-4xx1000)/(10-10^-4)`
`=0*01A` in parallel.
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