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In the circuit, shown in figure. R=5000O...

In the circuit, shown in figure. `R=5000Omega`. If key `K_1` is closed, galvanometer shows a deflection of 30 scale division. On closing key `K_2` and making `S=20Omega`, the deflection of galvanometer reduces to 15 division. The resistance of galvanometer is

A

`50Omega`

B

`30Omega`

C

`20Omega`

D

`15Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
`G=(RS)/(R-S)=(5000xx20)/(5000-20)=20Omega`
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