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In the circuit shown in figure. Ammeter ...

In the circuit shown in figure. Ammeter A is a galvanometer of resistance `60Omega` shunted with resistance `0*02Omega`. What is the current recorded by ammeter?

A

`0*5A`

B

`1*0A`

C

`2*0A`

D

`10A`

Text Solution

Verified by Experts

The correct Answer is:
B
Resistance of ammeter,
`G^'=(GS)/(G+S)=(60xx0*02)/(60+0*02)`
`:.` Current `I=(E)/(R+G^')`
`=(3*0)/(3*0+((60xx0*02)/(60+0*02)))=1*0A`
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